the area of rectangular plot is 528 m square the length of a plot is one more than twice its breadth we need to find the length and the breadth of the plot
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Let the breadth =b m
length = l =(2b+1)m
area =528m²
l*b= 528
(2b+1)b-528=0
2b²+b-528=0
2b²+33b-32b-528=0
b(2b+33)- 16(2b+33)=0
(2b+33)(b-16)=0
2b+33=0 or b-16=0
b should not be zero
therefore
b-16=0
b=16
breadth = 16m
length =l= 2b+1=2*16+1=32+1=33m
Let the breadth =b m
length = l =(2b+1)m
area =528m²
l*b= 528
(2b+1)b-528=0
2b²+b-528=0
2b²+33b-32b-528=0
b(2b+33)- 16(2b+33)=0
(2b+33)(b-16)=0
2b+33=0 or b-16=0
b should not be zero
therefore
b-16=0
b=16
breadth = 16m
length =l= 2b+1=2*16+1=32+1=33m
Answered by
9
Given:-
- Area of rectangular plot is 528 m².
- Length of plot is one meter more than twice the breadth.
To Find:-
- Find the length and breadth of plot?
Solution:-
- Let the breadth of rectangular plot be x m.
Therefore,
Length = One meter more than twice breadth.
=> (2x + 1) m
We know that,
Area of Rectangle = Length × Breadth
According to the questions:-
=> 528 = l × b
=> 528 = (2x + 1)(x)
=> 528 = 2x² + x
=> 0 = 2x² + x – 528
Now,
=> 2x² + x – 528
=> 2x² – 32x + 33x – 528
=> 2x (x – 16) + 33 (x – 16)
=> (2x + 33) (x – 16)
=> (2x + 33) = 0 or (x – 16) = 0
=> 2x = –33 or x = 16
Since, x cannot be negative.
=> x = 16
- Breadth = 16m
Length => 2x + 1
=> 2(16)+1
=> 32 + 1
=> 33 m
- Length = 33m
Hence, the length is 33m and breadth is 16m of plot.
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