Math, asked by Abhay31333, 1 year ago

The area of rhombus in 102 cm square. If its perimeter is 24 cm find its altitude.

Answers

Answered by TooFree

126

Given Perimeter = 24

$\boxed {\text {Length = Perimeter } \div 4 }$

Length = 24 ÷ 4 = 6 cm

$\boxed {\text {Area of Rhombus = Length }\times { \text {height}}}$

6 x height = 102

height = 102 ÷ 6 = 17 cm

Answer: Altitude = 17 cm

Abhay31333: Area of rhombus is diaognal1 × diaognal2

Abhay31333: 2area = d1 × d2

Abhay31333: i send you wrong formula first time

TooFree: I understand which formula you are referring to when you said the diagonals. There are a few ways to find the area of rhombus. Using the diagonal method (multiply them and then divide by 2) or use the base length x the height (which is also applicable to parallelograms)

Abhay31333: Thank you

Answered by harpreethl436

Answer:

Given Perimeter = 24

\boxed {\text {Length = Perimeter } \div 4 }

Length = Perimeter ÷4

Length = 24 ÷ 4 = 6 cm

\boxed {\text {Area of Rhombus = Length }\times { \text {height}}}

Area of Rhombus = Length ×height

6 x height = 102

height = 102 ÷ 6 = 17 cm

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