Question

the area of rhombus is 20cm square if one of its diagonal is 5 cm find the sides of a triangle
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Answer 1

Answer:

some data is missing in your question

Answer 2

AO = 16 cm. (half of AC)

AB = 20 cm.

As per Pythagoras Theorem,

AB^2 = AO^2 + BO^2

BO^2 = AB^2 - AO^2

BO^2 = 20^2 - 16^2

BO^2 = 400 - 256

BO^2 = 144

BO = 12 cm. (Square Root of 144)

BD = 24 cm. (Double of BO)

Now, we know the lengths of both diagonals of the Rhombus, i.e. AC = 32 cm., BD = 24 cm.

Area of Rhombus = 32*24/2 = 384 sq.cm