Question

The area of rhombus is 2140m² and one of the diagnols is 164 m. Find the length of the other diagnols​

Answer 1

Formula of Area of Rhombus =

\frac{1}{2}\times\:Product\:of\:its\:diagonals

2

1

×Productofitsdiagonals

Given Area = 2140 m^2m

2

Length of 1 Diagonal(p) = 164 m

We have to find the length of 2nd Diagonal. Let it be q.

Therefore,

Area of Rhombus = 2140m^2m

2

\frac{1}{2}\times\:p\times\:q

2

1

×p×q = 2140

\frac{1}{2}\times\:164\times\:q

2

1

×164×q = 2140

164\times\:q\:=\:2140\times\:2164×q=2140×2

q\:=\:\frac{2140\times\:2}{164}q=

164

2140×2

q\:=\:26.097(approx.)q=26.097(approx.)

Hence, Required answer is 26.097m

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