Question

The area of rhombus is 48.6 cm square. If one diagonals
is 12 cm find the other diagonal?​

Answer 1

Step-by-step explanation:

Area of rhombus=1/2*diagonal 1*diagonal2

48.6=1/2*12*diagonal 2

48.6=6*diagonal 2

diagonal 2=48.6/6

diagonal 2=8.1

other diagonal=8.1 cm

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Answer 2

Given:

• Area of Rhombus is 48.6 sq. cm.
• One Diagonal is 12 cm.

To Find:

• The Other Diagonal.

Solution :

As we know that,

⋆ Area of Diagonal = (d₁ × d₂)/2.

Here,

• d₁ = First Diagonal.
• d₂ = Second Diagonal.

➜(12 × d₂)/2 = 48.6 sq. cm.

➜ 12d₂ = 48.6 × 2 sq. cm.

➜ 12d₂ = 97.2 sq. cm.

➜ d₂ = 97.2/12

➜ d₂ = 8.1 cm.

Therefore, The Other Diagonal is 8.1 cm.

Verification:

➜Area of Diagonal = (d₁ × d₂)/2.

➜(12 × 8.1)/2 = 48.6 sq. cm.

➜97.2/2 = 48.6sq. cm.

➜48.6 sq. cm = 48.6 sq. cm.

LHS = RHS.

Hence, Verified.