The area of rhombus is 96 cm sq.if one of its diagonal is 16 cm then find out the of its side
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Area of rhombus=1/2×diagonal1×diagonal2
96 cm sq.=1/2×16×d2cm
96cm sq.=8d2cm
96/8cm=12cm=d2
Then by taking any one triangle and by applying Pythagoras theorem we can do it further
96 cm sq.=1/2×16×d2cm
96cm sq.=8d2cm
96/8cm=12cm=d2
Then by taking any one triangle and by applying Pythagoras theorem we can do it further
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