Question

The area of Rhombus is412.One of its diagonals is8.2, find the other diagonal.

Answer 1

Step-by-step explanation:

Area of a rhombus $\tt =\frac{1}{2} \times$ Product of diagonals.

Let the length of the required diagonal be $\tt d_{2} \:\:cm$. Then,

$\pmb{ \tt 412=\frac{1}{2} \times 8.2 \times d_{2}} \\ \\ \pmb{ \tt\Rightarrow d_{2}=\frac{412 \times 2}{8.2}= \frac{824}{8.2} \: \: cm = 100.48 \: \: cm }$