Question

The area of Rhombus whose diagonals are 14 cm. and 15 cm........... .

Answer 1

Step-by-step explanation:

Question :-

• Find the area of rhombus whose diagonals measures 14 cm and 15 cm.

To Find :-

• Area of rhombus.

Solution :-

Given :

• Diagonal (1) = 14 cm
• Diagonal (2) = 15 cm

By using the formula,

${\sf{\longrightarrow Area\ of\ rhombus\ =\ \dfrac{1}{2} \times d_1 \times d_2}}$

Where,

• d = length of the diagonals

According to the question, by using the formula, we get :

${\sf{\longrightarrow Area\ of\ rhombus\ =\ \dfrac{1}{2} \times d_1 \times d_2}}$

${\sf{\longrightarrow \dfrac{1}{\cancel2} \times \cancel{14} \times 15}}$

${\sf{\longrightarrow 7 \times 15}}$

${\sf{\longrightarrow 105\ cm^2}}$

$\therefore$ Hence, area of rhombus is 105 cm².

More To Know :-

$\begin{gathered}\boxed{\begin {minipage}{9cm}\\ \dag\quad \Large\underline{\bf Formulas\:of\:Areas:-}\\ \\ \star\sf Square=(side)^2\\ \\ \star\sf Rectangle=Length\times Breadth \\\\ \star\sf Triangle=\dfrac{1}{2}\times Breadth\times Height \\\\ \star \sf Scalene\triangle=\sqrt {s (s-a)(s-b)(s-c)}\\ \\ \star \sf Rhombus =\dfrac {1}{2}\times d_1\times d_2 \\\\ \star\sf Rhombus =\:\dfrac {1}{2}p\sqrt {4a^2-p^2}\\ \\ \star\sf Parallelogram =Breadth\times Height\\\\ \star\sf Trapezium =\dfrac {1}{2}(a+b)\times Height \\ \\ \star\sf Equilateral\:Triangle=\dfrac {\sqrt{3}}{4}(side)^2\end {minipage}}\end{gathered}$

Answer 2

Answer:

• 105 cm²

Step-by-step explanation:

Given

• D1 = 14 cm
• D2 = 15 cm
• Area = ?

To find

• Area

Formula

• Area of Rhombus = ½ × product of its diagonal

Solution

We know that,

Area of Rhombus = ½ × product of its diagonal

→ ½ × 14 × 15

→ 7 × 15

→ 105

Hence,

• Area of rhombus = 105cm².

$\rule{160pt}{0pt}$

Additional Information

Area of Rectangle

$\sf \: l \: \times \: b$

Area of square

$\sf {s}^{2}$

Area of Parallelogram

$\sf \: b \: \times \: h$

Area of circle

$\pi \: {r}^{2}$