Question

the area of rhombus whose side is 8cm and altitude is 6cm, if one of the diagnol is 10cm long, find the length of other diagnol.​

Answer 1

Given :-

side of the rhombus = 8cm

altitude of the rhombus = 6cm

therefore it's area = b × h (since rhombus is also a parallelogram)

= 8 × 6

= 48cm²

another formula for the area of a rhombus is 1/2 × d1 × d2 where d1 and d2 are the diagonals of the Rhombus.

we are given the length of one diagonal that's 10cm

=> 1/2 × d1 × d2 = 48cm²

=> 1/2 × 10 × d2 = 48cm²

=> 5 × d2 = 48cm²

=> d2 = 48/5

=> d2 = 9.6cm

hence, the length of another diagonal is 9.6cm