the area of right angle triangle is 20sq ft and it's perimeter is 40 ft then lengh of its hypotenuse is
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Given : the area of right angle triangle is 20sq ft and it's perimeter is 40 ft
To Find : length of its hypotenuse is
Solution:
Perpendicular legs = x , y
Area = (1/2)xy = 20
=> xy = 40
Hypotenuse = √x² + y²
Perimeter = x + y + √x² + y² = 40
x + y = 40 - √x² + y²
=> x² + y² + 2xy = 1600 + x² + y² - 80√x² + y²
=> 2xy = 1600 - 80√x² + y²
=> xy = 800 - 40√x² + y²
xy = 40
=> 40 = 800 - 40√x² + y²
=> 1 = 20 - √x² + y²
=> √x² + y² = 19
length of its hypotenuse is 19 ft
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