the area of right angled isosceles triangle is 12 1/2sqm. find the length of its hypotenuse
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1/2xbxh = 121/2
1/2x(b)² = 121/2 [b = h]
(b)²=121
b=11
√(b²)+(h)² = H
√(121+121) = H
√242 = H
H = 15.55
1/2x(b)² = 121/2 [b = h]
(b)²=121
b=11
√(b²)+(h)² = H
√(121+121) = H
√242 = H
H = 15.55
Answered by
0
area of right angled isosceles triangle = 12 1/2 m²
1/2*b*b = 25/2
b² = 25
b = 5 m
hypotenuse = √(base² + altitude²)
= √(5² + 5²)
= √(25 + 25)
= √50
= 5√2 m
1/2*b*b = 25/2
b² = 25
b = 5 m
hypotenuse = √(base² + altitude²)
= √(5² + 5²)
= √(25 + 25)
= √50
= 5√2 m
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