Question

the area of right angled triangle id 54 cm sq. One of its leg 12 cm long . Find the perimeter​

Answer 1

Answer:

Given area=54cm^2

One of the side = 12cm

Let us consider base as 12cm and height as x

Now

Area = 1/2 *b*h

54=1/2*12*h

54=6*h

h =54/6

h=9

Now for perimeter we need to find hypotenuse

Thus by pythagoros

a^2 +b^2 =c^2

12^2 +9^2 =c^2

225=c^2

Thus, c=15

Now perimeter

P =a+b+c

=12+9+15

=36cm