The area of right angled triangle is 20 sq ft and it's perimeter is 40 ft. Then, length of its hypotenuse is.
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Solution :-
Let
- Perpendicular = P
- Base = B
- Hypotenuse = H
So,
→ (1/2) * P * B = 20
→ P•B = 40
and,
→ P + B + H = 40
→ P + B = (40 - H)
→ (P + B)² = (40 - H)²
→ P² + B² + 2P•B = 1600 + H² - 2•40•H
using pythagoras theorem,
→ H² + 2 * 40 = 1600 + H² - 80H
→ 80H = 1600 - 80
→ 80H = 1520
→ H = 19 (Ans.)
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