Math, asked by ninadm1887, 15 days ago

The area of right angled triangle is 270cm and its sides are in ratio 5:12:13
Then find its perimeter

Answers

Answered by sienasgalaxy
0

Answer:

sorry i don't think i know Sorry

Answered by dhairya49majethia
0

Answer:

Step-by-step explanation:

Let the sides of the triangle be 5k, 12k, 13k, for some positive integer k. One thing we should notice immediately is that this is a right triangle, because (5k)^2 + (12k)^2 = 25k^2 + 144k^2 = 169k^2 = (13k)^2, thus satisfying the Pythagorean theorem, which is if and only if. So the two smaller sides are the legs, and the the biggest side is the hyphotenuse. Since the legs form a right angle, when calculating the area of the triangle, one of them acts as the base, and the other as the height. So then we have:

Area = ½ * base * height = 270cm^2

1/2 * 5k * 12k = 270cm^2

60k^2 = 540cm^2

k^2 = (540/60) cm^2 = 9cm^2

Since k is positive, k = √(9cm^2) = 3cm

Finally, the sides of the triangle are 5*3cm = 15cm, 12*3cm = 36cm, and 13*3cm = 39cm.

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