The area of right triangle is 24 cm square if one of the side containing the right angle is 8cm find the length of its hypotenuse
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Answered by
22
Area of right triangle = 1/2×B×P
24cm² =1/2×B×8
B = 24×2/8
B = 3×2 = 6cm
Therefore,
B = 6, P = 8, H =?
We know that,
(H)² = (B)²+(P)²
(H)² =(6)²+(8)²
(H)² = 36+64= 100
H = ✓100 = 10cm
Hence,
Hypotenuse = 10cm
24cm² =1/2×B×8
B = 24×2/8
B = 3×2 = 6cm
Therefore,
B = 6, P = 8, H =?
We know that,
(H)² = (B)²+(P)²
(H)² =(6)²+(8)²
(H)² = 36+64= 100
H = ✓100 = 10cm
Hence,
Hypotenuse = 10cm
Answered by
4
heya frnd!
here's ur answer...
given the height of the right triangle=8cm
area of the right triangle=24cm²
→1/2×b×h=24cm²
→1/2×b×8=24cm²
→4×b=24cm²
→b=24/4
→b=6cm
verification:-
area of the right triangle=1/2×b×h
=1/2×6×8
=3×8
=24cm²
hence verified
thus the base of right triangle is 6cm.
we all know Pythagoras thereom in which a²+b²=c²
here a is the height means the side containing right angle and b is the base. c is the hypotenuse.
→ a² + b² = c²
→ 8² + 6² = c²
→ 64 + 36 = c²
→ 100 = c²
→ c = √100
→ c = 10cm
verification:-
→a²+b²=c²
→c²=10²
=100
→8²+6²
→64+36
=100
hence verified.
thus the hypontuse of the right triangle is 10cm.
hope this helps..!
here's ur answer...
given the height of the right triangle=8cm
area of the right triangle=24cm²
→1/2×b×h=24cm²
→1/2×b×8=24cm²
→4×b=24cm²
→b=24/4
→b=6cm
verification:-
area of the right triangle=1/2×b×h
=1/2×6×8
=3×8
=24cm²
hence verified
thus the base of right triangle is 6cm.
we all know Pythagoras thereom in which a²+b²=c²
here a is the height means the side containing right angle and b is the base. c is the hypotenuse.
→ a² + b² = c²
→ 8² + 6² = c²
→ 64 + 36 = c²
→ 100 = c²
→ c = √100
→ c = 10cm
verification:-
→a²+b²=c²
→c²=10²
=100
→8²+6²
→64+36
=100
hence verified.
thus the hypontuse of the right triangle is 10cm.
hope this helps..!
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