Question

The area of rombus in which a diagonal is of length 66 cm and 48 cm:-
a) 114 cm^2 b) 228 cm^2 c) 1584 cm^2 d) 3168 cm^2​

Answer 1

Answer:

1584cm^2

Step-by-step explanation:

Diagonals of the rombous are- 66cm and 48cm

diagonal1- 66cm

diagonal2- 48cm

area of the rombous is 1/2×d1×d2

so,1/2×66×33

= 33×48

=1548cm^2

Answer 2

Before, finding the answer. Lets find out on how we can find the answer.

• Formula for Area of Rhombus :

$\sf Area = \purple{ \dfrac{1}{2} } \times \red {d1} \times \pink{d2}$

Where,

D1 = Diagonal 1

D2 = Diagonal 2

• Here, we have to first multiply diagonal 1 and diagonal 2.
• Then, we must divide it by 2.

______________

Given :

Diagonal 1 = 66 cm

Diagonal 2 = 48 cm

To find :

Area of Rhombus

Solution :

$\sf Area \: of \: Rhombus = \dfrac{1}{2} \times d1 \times d2$

$\sf = \dfrac{1}{2} \times 66 \times 48$

$\sf = \dfrac{1}{2} \times 3168$

$\sf = \dfrac{3168}{2}$

$\sf = 1584$

Hence, the area of Rhombus is 1584 cm².

★ Know more :

To know more about Rhombus. Go to the following link :

• https://brainly.in/question/35675305