The area of sector is 1,540 sq. m. The sector subtends 50°at center, then find the radius of circle.
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answer is 59.39 m
approx
approx
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3
Area of sector = Ф/360 × πr²
1540 = 50/360 × 22/7 × r²
r² = 1540 × 360/50 × 7/22
r² = 3528
r = √3528
r = 59.39696961966999 cm
r = 59.4 cm (approx)
:) Hope This Helps!!!
1540 = 50/360 × 22/7 × r²
r² = 1540 × 360/50 × 7/22
r² = 3528
r = √3528
r = 59.39696961966999 cm
r = 59.4 cm (approx)
:) Hope This Helps!!!
nitthesh7:
Step 2: Find the divisor, such that its square is either equal or less than the number under first bar from the left. Here divisor and first digit of quotient will be same. Now do the division and get the remainder
And it is to be selected in such a way that, when new divisor is multiplied by this next digit of quotient, the product will be equal or less than the new dividend (as calculated in step 3)
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