The area of sector is 1,540 sq. m. The sector subtends 50°at center, then find the radius of circle.
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answer is 59.39 m
approx
approx
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Area of sector = Ф/360 × πr²
1540 = 50/360 × 22/7 × r²
r² = 1540 × 360/50 × 7/22
r² = 3528
r = √3528
r = 59.39696961966999 cm
r = 59.4 cm (approx)
:) Hope This Helps!!!
1540 = 50/360 × 22/7 × r²
r² = 1540 × 360/50 × 7/22
r² = 3528
r = √3528
r = 59.39696961966999 cm
r = 59.4 cm (approx)
:) Hope This Helps!!!
nitthesh7:
Step 2: Find the divisor, such that its square is either equal or less than the number under first bar from the left. Here divisor and first digit of quotient will be same. Now do the division and get the remainder
Step 3: Now bring down the next digits, under second bar and place them to the right of remainder. This will become new dividend.
Step 4: Starting digit(s) of new divisor is equal to twice of first digit of quotient (calculated in step 2)
Step 5: Now the digit at one�s place of new divisor is equal to next digit of quotient.
And it is to be selected in such a way that, when new divisor is multiplied by this next digit of quotient, the product will be equal or less than the new dividend (as calculated in step 3)
And it is to be selected in such a way that, when new divisor is multiplied by this next digit of quotient, the product will be equal or less than the new dividend (as calculated in step 3)
Step 6: Divide and get the new remainder.
Step 7: This process is to be repeated till all numbers are used under the bars.
Oky
I got it now
Tnx
no mention sis
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