the area of sector is 1 by 5 of the area of the circle containing it
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It is given that ,
Area of the sector ( A ) = 15π sq cm
Radius of the circle ( r ) = 6 cm
We know that ,
1 ) Area of the sector ( A ) = ( x°/360 ) × πr²
Where , x is sector angle ,
2 ) length of the arc ( l ) = ( x°/360 ) × 2πr
Now ,
1 ) ( x°/360 ) × πr² = A
( x°/360 ) × π × 6² = 15π
x° = ( 15π × 360 )/( π × 36 )
x° = 150
2 ) length of the arc ( l ) = ( x/360 ) × 2πr
l = ( 150/360 ) × 2 × π × 6
l = 5π cm
aliya5210:
sorry wrong answer
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