The area of sector of a circle of radius 8 cm is 16 pi sq cm find the length of the corresponding arc
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(theta/360) ×π(r)^2 = area of sector
(theta/360) ×π×(8)^2 = 16π
theta = 90°
length of arc = (theta/360) × 2πr
length of arc = (90/360) × 2π ×8
length of arc = 4π cm = 12.56 cm
(theta/360) ×π×(8)^2 = 16π
theta = 90°
length of arc = (theta/360) × 2πr
length of arc = (90/360) × 2π ×8
length of arc = 4π cm = 12.56 cm
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