the area of smaller piston of a hydraulic press is 1 cm sq and that of larger piston is 22 cm sq . how much weight can be raised on the larger piston by a 200kg f exerted on the smaller piston
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Explanation:
a =1 cm^2 A=22 cm^2
f =200 Kgf =200×10 N
F=ma
f/a=F/A
200×10/1×10^-4 =m×10 /22×10^-4
=200×22
=4400Kg
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Given,
Area of smaller piston=1cm sq.
Area of larger piston=22cm sq.
Exerted force on the smaller piston=200kgf
To Find,
Amount of weight raised.
Solution,
Here, area of smaller one=1cm sq=10^-4m²
Area of larger one=22cm sq=22×10^-4m²
Weight=f=200kgf=200×9.8N
We know F= m×a N
f/a=F/A
Putting all those value in this equation,
200×9.8/10^-4=m×9.8/22×10^-4
⇒m=200×22=4400kg.
Hence, 4400kg weight can be raised on the larger piston by 200kgf exerted on the smaller piston.
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