Physics, asked by Rupinder001, 6 months ago

the area of smaller piston of a hydraulic press is 1 cm sq and that of larger piston is 22 cm sq . how much weight can be raised on the larger piston by a 200kg f exerted on the smaller piston ​

Answers

Answered by bhavneet735
8

Explanation:

a =1 cm^2 A=22 cm^2

f =200 Kgf =200×10 N

F=ma

f/a=F/A

200×10/1×10^-4 =m×10 /22×10^-4

=200×22

=4400Kg

Attachments:
Answered by Hansika4871
2

Given,

Area of smaller piston=1cm sq.

Area of larger piston=22cm sq.

Exerted force on the smaller piston=200kgf

To Find,

Amount of weight raised.

Solution,

Here, area of smaller one=1cm sq=10^-4m²

Area of larger one=22cm sq=22×10^-4m²

Weight=f=200kgf=200×9.8N

We know F= m×a N

f/a=F/A

Putting all those value in this equation,

200×9.8/10^-4=m×9.8/22×10^-4

⇒m=200×22=4400kg.

Hence, 4400kg weight can be raised on the larger piston by 200kgf exerted on the smaller piston.

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