the area of square field is 1024sq mt find it's perimeter
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Answered by
3
Answer:
area of square field= 1024
(side)^2=1024
side=√1024
side=32
perimeter of square field = 4×side
=4×32
=128
Answered by
1
Answer:
we know that
the area of a square =s^2
1024=s^2
Step-by-step explanation:
we know that
the area of a square =s^2
1024=s^2
transpose square
s=square root of 1024
s=square root of 1024
s=32
we got side of a square
then its perimeter is 4s
4s = 4*32
=128cm
therefore the perimeter of square is 128 cm
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