Question

The area of square field is 2209 sq.m then find its perimeter​

Answer 1

SOLUTION

GIVEN

The area of square field is 2209 sq.m

TO DETERMINE

The perimeter

EVALUATION

Let side of the square = a meter

Then area of the square = a² sq.m

So by the given condition

$\displaystyle \sf{ {a}^{2} = 2209}$

$\displaystyle \sf{ \implies a = \sqrt{2209} }$

$\displaystyle \sf{ \implies a = 47 }$

Hence the required perimeter

= 4a meter

= 4 × 47 meter

= 188 meter

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