Math, asked by challakavya99, 10 months ago

the area of square field is 4225 metre square find the area of rectangular field whose perimeter is equal to the perimeter of the square field and whose length is twice of its breadth​

Answers

Answered by Isighting12
3

Answer:

Area =  3755.5 m^{2}

Step-by-step explanation:

Area of the square field = 4225 m^{2}

Side of the square = \sqrt{4225}

                                = 65 m

Perimeter of square field = 4x

                                          = 4( 65 )m

                                          = 260 m  

Let the length and breadth of the rectangle be l & b respectively

ATQ

l = 2b                        (equation 1)

also perimeter of square is equal to perimeter of rectangle

=> 2(l + b) = 260 m

=> 2(3b) = 260 m                             (from equation 1)

=> b = \frac{260}{6}

=> b = \frac{130}{3} m

and l = 2(\frac{130}{3})

          = \frac{260}{3} m

Area of rectangular field = l * b

                                         = \frac{260}{3} * \frac{130}{3}

                                         = \frac{3380}{9}

                                         = 3755.5 m^{2}

Answered by avtarsingh56524
0

Answer:

I know I am teacher its answer is only 23cm sq

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