Question

the area of square field is 5184 m². find the area of rectangular field. whose perimeter is equal to perimeter of square field and whose length is twice of its breadth​

Answer 1

Answer:

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Step-by-step explanation:

given,

the area of square is=5184m²

s×s=5184

s²=5184

s=√5184

s=72

according to problem,

l=2x

b=x

we know that,

perimeter of square=perimeter of rectangle

4s=2(l+b)

4×72=2(2x+x)

288=6x

x=288/6

x=48

from problem,

l=2x

=2×48

=96

b=x

=48

therefore length is 96

              breadth is 48

area of rectangle = l × b

                           = 96 × 48

                            =4608 m²

Answer 2

Given:-

• Area of square field = 5184 m².

To Find:-

• Area of rectangle.

Formula to be used:-

• Perimeter of square = 4a

• Perimeter of rectangle = 2 (l + b)

Solution:-

• Let the side of square field as a.

Then,

• ⇒ a² = 5184 m²
• ⇒ a = √5184 m
• ⇒ a = 2 × 2 × 2 × 9 = 72 m

Now,

• Perimeter of square = 4a
• Perimeter of square = 4(72)
• Perimeter of square = 288 m

Now,

• Perimeter of rectangle = 2 (l + b)
• ⇒ 288 = 2 (l + b)

As length is twice of its breadth,

• ⇒ 288 = 2 × (2b + b)
• ⇒ 288 = 2 × 3b
• ⇒ 288/2 = 3b
• ⇒ 144 = 3b
• ⇒ 144/3 = b
• ⇒ b = 48

• Here, breadth is 48 m

Now length,

• Length = 2 × 48 = 96 m

Now, Area of rectangle  

• Area of rectangle = l × b

• Area of rectangle = 96 × 48

• Area of rectangle = 4608 m².

✝ Hence, the Area of rectangle is 4608 m² ✝