Question

The area of square field is 5184 m2. Find the area of a rectangle field, whose perimeter is equal to the perimeter of the sqare firldand whose length is twice of its breath

Answer 1

given,

the area of square is=5184m²

s×s=5184

s²=5184

s=√5184

s=72

according to problem,

l=2x

b=x

we know that,

perimeter of square=perimeter of rectangle

4s=2(l+b)

4×72=2(2x+x)

288=6x

x=288/6

x=48

from problem,

l=2x

=2×48

=96

b=x

=48

therefore length is 96

              breadth is 48

area of rectangle = l × b

                           = 96 × 48

                            =4608 m²

Answer 2

Answer:

4608 m²

Step-by-step explanation:

Area Of square filed = Side²

Side² = 5184 m²

=> side² =  72² m²

=> side = 72 m

Perimeter = 4 *  side = 4 * 72 = 288 m

Rectangle has Length = Twice Breadth

so Perimeter of rectangle = 2 (2B + B) = 288

=> 6B = 288

=> B = 48

L = 2B = 2 * 48 = 96

Area of rectangular field = Length * Breadth

= 48 * 96

= 4608 m²