the area of square field is 5184 metre square a regtangular fieldwhose length is twice its breadthhas its perimetre equal to perimetre of square field find the area of rectangular field
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given,
the area of square is=5184m²
s×s=5184
s²=5184
s=√5184
s=72
according to problem,
l=2x
b=x
we know that,
perimeter of square=perimeter of rectangle
4s=2(l+b)
4×72=2(2x+x)
288=6x
x=288/6
x=48
from problem,
l=2x
=2×48
=96
b=x
=48
therefore length is 96
breadth is 48
area of rectangle = l × b
= 96 × 48
=4608 m²
shivtej47:
hi
Answered by
0
here is your answer mate .......
given ar of sq = a^2= 5184
a = √5184= 72m
then perimeter = 4a = 4×72= 288m
let the breadth of rectangle be x then length 2x.
then...
2x+x=288=3x=288
x=288/3=96m
and length = 2×96=192
then area of rectangular field = l×b
192×96 = 18432m^2
ans....
hope this helps you...mark as brainliest
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