Question

The area of square field is 720801 m^2 .A man cycles along its boundary at 28 km/hr. In how much time will he return to the starting point

Answer 1

Answer:

$\large{\underline{\boxed{\sf Time = 679.2 \: seconds }}}$

Explanation:

Given that ;

Area of square field = 720801 m²

⇒ (side)² = 720801

⇒ side = ± √720801

⇒ side = ± 849

Since, the length of square can not be negative. Thus, side = 849 m.

Now, we know that the perimeter of square is also the total distance covered.

⇒ Perimeter of square = 4 * side

⇒ Perimeter = 4 * 849

⇒ Perimeter = 3396 m

So, here we have -

• Distance = 3396 m
• Speed = 18 km/h = 5 m/s.

Time taken = $\rm \dfrac{Distance }{Speed }$

⇒ Time = $\sf \dfrac{3396}{5}$

⇒ Time = 679.2 seconds.

Hence, the time taken is 679.2 seconds.

Answer 2

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