Question

The area of square fielf is 60025sqm.A man cycles the boundary at 18km/h.In how much time will he return at the starting point

Answer 1

Answer:196 sec

Explanation

Area=60025 sqm (Given)

We know that

Area of sqaure=(side)^2

60025=(side)^2

$side = \sqrt{60025}$

side=245 m

Now,the perimeter of boundary of the field=4×side

=4×245

=980 m

We also know speed=distance/time

First changing speed in m/s

Speed=18×5/18=5 m/s

Now speed=d/t

5 =980/t

t=9880/5

=196 sec

Therefore,in 196(3min 6 sec)he return at the starting time

Answer 2

» Area of a square field is 60025 m². A man cycles the boundary at 18km/h.

» Area = 60025 m²

Speed = 18 km/hr

=> 18 × $\frac{5}{18}$ = 5 m/sec

___________ [ GIVEN ]

• We have to find that how much time man will take to return at the staring point.

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Solution:

Area = 60025 m²

We know that ..

→ Area of square = side × side

→ 60025 = side²

→ side = √60025

→ side = 245 m

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Perimeter of square = 4 × side

→ 4 × 245

→ 980 m

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Now ..

Distance = Speed × time

time = $\dfrac{distance}{speed}$

Here ..

distance = 980 m and speed = 5 m/s

→ time = $\dfrac{980}{5}$

→ time = 196 sec

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A man takes 196 sec to return at the staring point.

__________ [ ANSWER ]

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