Question

The area of square is 225cm². Find the perimeter of the square​

Answer 1

Given :

• area of the square is 224 cm²

To Find :

• Perimeter of the square

Formulas to be used :

• Area of square = (side)²
• Perimeter of square = 4 × (side)

Solution :

Area of square = (side)²

=> 225 = (side)²

=> side = √225

=> side = 15 cm

Perimeter of square = 4 × (side)

=> 4 × 15

=> 60 cm

Hence, Perimeter of the square is 60 cm

Answer 2

$\huge\rm\underline\blue{GIVEN:}$

• $\large\rm{Area\:of\:square\:=\:225cm^2}$

$\huge\rm\underline\blue{TO\:FIND:}$

• $\large\rm{Perimeter\:of\:the\:square}$

$\huge\rm\underline\blue{SOLUTION:}$

$\large\rm{Area\:of\:square\:=\:225cm^2}$

$\rm\bold{\boxed{Area\:of\:square\:=\:(side)^2}}$

$\large\rm{\implies{(side)^2\:=\:225}}$

$\large\rm{\implies{side\:=\:\sqrt{225}}}$

$\large\rm{\implies{side\:=\:15cm}}$

$\rm\bold{\boxed{Perimeter\:of\:square\:=\:4(side)}}$

$\large\rm{\implies{Perimeter\:=\:4(15)}}$

$\large\rm{\implies{Perimeter\:=\:60cm}}$

$\large\rm{\therefore{Perimeter\:of\:square\:=\:60cm}}$

$\huge\rm\underline\pink{Additional\:Information:}$

• $\large\rm{Perimeter\:of\:rectangle\:=\:2(l+b)}$
• $\large\rm{Area\:of\:rectangle\:=\:L(B)}$

$\large\rm{L\rightarrow{Length\:of\:rectangle}}$

$\large\rm{B\rightarrow{Breadth\:of\:rectangle}}$