Question

The area of square is4900cm find the length of its diagonal

Answer 1

$area = {side}^{2} \\ 4900 = {side}^{2} \\ side = \sqrt{4900} = 70cm \\ \\ by \: pythagoras \: theorem \\ {diagonal}^{2} = {side}^{2} + {side}^{2} \\ diagonal = \sqrt{ {70}^{2} + {70}^{2} } \\ diagonal = \sqrt{4900 + 4900} \\ diagonal = \sqrt{9800} = 98.99cm$