the area of square whose perimeter is 48 m
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Answered by
32
In a square, all of the side lengths are congruent.
The perimeter of a square is the sum of the sides. We can express this in an equation.
P=4s
Where P=perimeter and s=side length
Now, substitute 48 for P and solve for s.
48=4s
48/s=4s/4
12=s
Now that we know the side lengths, we can calculate the area.
The area of a square is equal to the length multiplied by the width.Since the length and width are both 12, then we will multiply 12 by itself.
12*12=144
The area of a square with the perimeter of 48m is 144m^2.
The perimeter of a square is the sum of the sides. We can express this in an equation.
P=4s
Where P=perimeter and s=side length
Now, substitute 48 for P and solve for s.
48=4s
48/s=4s/4
12=s
Now that we know the side lengths, we can calculate the area.
The area of a square is equal to the length multiplied by the width.Since the length and width are both 12, then we will multiply 12 by itself.
12*12=144
The area of a square with the perimeter of 48m is 144m^2.
Answered by
17
Answer:
side of the square = perimeter _4=48_4=12 m
area of the square = side× side
=12×12= 144m^2
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