Question

The area of the amrita rectangular land is 200 sqm and perimeter of it's 180m by calculating let us write the length and breadth of amrita landing

Answer 1

Answer:

Length is 50 m and Breadth is 40 m.

Step-by-step explanation:

let the length be x and breadth be y.

Perimeter of rectangle = 2(l+b)

It is given that perimeter is 180 m.

So,  2(x+y) = 180

 x + y = 90

y = 90 - x  ..........(i)

Area of rectangle = lb

It is given that the area is 200 m².

So, xy= 200             .............(ii)

Putting value of y from (i) in (ii),

x(90-x) = 200

90x - x² - 200 = 0

Dividing whole equation by (-),

-90x +x² +200 = 0

x² - 90x + 200 = 0

x² - 40x - 50x + 200 = 0

(x-40) (x-50)=0

x = 40  and x=50.

Hence, x = 40 m and 50 m.

Therefore, there are two possible lengths 40m and 50m.

and y = 90-x

= 90 - 40 = 50m 

and 90 - 50 = 40m.

Hence, two possible pair are length = 50m and breadth = 40m.

But, this is not possible as length is never greater to breadth.

So, the possible length is 50 m and breadth is 40 m.