The area of the ΔAOB having vertices A(0, 6), O(0,0), and B(6, 0) is
a) 12 sq. units
b) 36 sq. units
c) 18 sq. units
d) 24 sq. units
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Given:-
Vertices, A(0,6) , O(0,0) , B(6,0)
To find:-
Area of triangle.
Solution:-
Area Of triangle = | x1(y2-y3) + x2(y3-y1) + x3(y1-y2) |
Where,
x1=0 , y1=6
x2=0 , y2=0
x3=6 , y3=0
Area => | 0(0-0) + 0(0-6) + 6(6-0) |
=> | 0+0+36 |
=> × 36
=> 18
Which is the required answer.
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