the area of the base of a conical tent is 154 square metre and that of its curved surface area is 550 square M find its slant height total surface area and volume
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area of base of conical tent = πr²
154 = 22/7 ×r²
r² = 7/22× 154
r² = 49
r = √49
r = 7m
curved surface area of cone = πrl
550 = 22/7×7×l
550/22 = l
25 = l. (slant height).
T.S.A. = πr(l+r)
= 22/7 × 7(25+7)
= 22× 32
= 704m²
volume of cone = 1/3πr²h
= 1/3× 22/7 × (7)²h
= 154/3 h. .......i)
l²= r²+h²
(25)² = (7)²+h²
625-49 = h²
√576 = h
h = 24 m
put h = 24m in .i) equation.
volume = 154/3× 24
= 1232m³. Ans
154 = 22/7 ×r²
r² = 7/22× 154
r² = 49
r = √49
r = 7m
curved surface area of cone = πrl
550 = 22/7×7×l
550/22 = l
25 = l. (slant height).
T.S.A. = πr(l+r)
= 22/7 × 7(25+7)
= 22× 32
= 704m²
volume of cone = 1/3πr²h
= 1/3× 22/7 × (7)²h
= 154/3 h. .......i)
l²= r²+h²
(25)² = (7)²+h²
625-49 = h²
√576 = h
h = 24 m
put h = 24m in .i) equation.
volume = 154/3× 24
= 1232m³. Ans
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