Question

The area of the base of a right circular cylinder is 15400 cm2 and its volume is 92400 cm'. Find the area of the curved surface.
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Answer 1

Answer:

volume of cylinder = pie x r square x h

92400 = 15400 x h

h = 6

volume of cylinder = pie x r square x h

92400 = 22/7 x r square x 6

92400 x 7 / 22 x 6 = r square

r square = 4900

r = 70

curved surface area = 2 x pie r x h

= 2 x 22/7 x 70 x 6

= 2 x 22 x 10 x 6

=2640 sq.cm.

mark brainliest

Answer 2

$\bf \red{ \underline{ \underline{given}}}$

• Area of base=15400cm²
• Volume of cylinder =92400cm

$\bf \red{ \underline{ \underline{to \: find \: out}}}$

The area of Curved surface =?

$\bf \red{ \underline{ \underline{solution}}}$

$volume \: of \: cylinder = \pi \: r {}^{2} h$

$volume \: of \: cylinder = (area \: of \: base) \times h$

$\purple{putting \: the \: value}$

$92400 = 15400 \times h$

$h = \frac{92400}{15400}$

$h = 6 \: cm$

Now, Area of base =15400 cm²

$\pi \: r {}^{2} = 15400$

$\frac{22}{7} \times r {}^{2} = 15400$

$r {}^{2} = \frac{7 \times 15400}{22}$

$r = \sqrt{4900}$

$\blue{r = 70 \: cm}$

Therefore,

Area of the Curved surface area =

$2\pi \: r \: h$

$= 2 \times \frac{22}{7} \times 70 \times 6 \: cm {}^{2}$

$\orange{= 2640}$