Question

the area of the base of a tent in the form of a right circular cone is 13.86 sq.metre. To make the tent a tripol of rupees 5775 is required and the price of 1 square metre of tripol is rupees 250. Find the height of the tent.​

Answer 1

Step-by-step explanation:

Radius of base of cylindrical portion=14m

Height of cylindrical portion=3m

Curved surface area of cylindrical part=2×

$22 \: \times 14 \: \times 3 \: \ \\7$

Height of conical part=13.5−3=10.5m

For conical part:r=14m,h=10.5m

1=

$\sqrt{(14) {}^{2} \: + (10.5) {}^{2} }$

=

$\sqrt{306.25}$

1=17.5

CSA of conical part= πrl =

$\frac{22}{7} \times 14 \times 17.5 = 770m {}^{2}$

∴Total area to be painted= (264+770)m² = 1034m²

Cost of painting=Rs. (1034×2)=Rs. 2068

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