Question

The area of the base of cylindrical tank is 38.5m^2 find the perimeter of the base.


quick it's urgent​

Answer 1

Answer :-

• The perimeter is 21.93m.

Step-by-step explanation:

To Find :-

• The perimeter of the base

Solution:

Given that,

• The area of the base of cylindrical tank = 38.5m²

∴ The radius of the tank is,

We know,

$\bigstar \: \boxed{\bf{Area \: of \: {base}_{(cylinder)} = \pi \: {r}^{2}}}$

Where,

• π = 22/7
• r = radius

Therefore,

$\bf{\longmapsto \: \pi \: {r}^{2} = 38.5} \\ \\ \\ \\ \bf{\longmapsto \: \dfrac{22}{7} \times \: {r}^{2} = 38.5} \\ \\ \\ \\ \bf{\longmapsto \: {r}^{2} = 38.5 \times \dfrac{7}{22}} \\ \\ \\ \\ \bf{\longmapsto \: {r}^{2} = \dfrac{38.5 \times 7}{22}} \\ \\ \\ \\ \bf{\longmapsto \: {r}^{2} = \dfrac{268.8}{22}} \\ \\ \\ \\ \bf{\longmapsto \: {r}^{2} = \cancel{\dfrac{268.8}{22}}} \\ \\ \\ \\ \bf{\longmapsto \: {r}^{2} = 12.21} \\ \\ \\ \\ \bf{\longmapsto \: r = \sqrt{12.21} } \\ \\ \\ \\ \bf{\longmapsto \: \orange{r = 3.49}}$

Hence, The radius is 3.49m. Now, perimeter :-

We know,

$\bigstar \boxed{\bf{Perimeter = 2 \: \pi \: r}}$

Therefore,

$\bf{\longmapsto \: 2 \: \pi \: r} \\ \\ \\ \\ \bf{\longmapsto \: 2 \times \: \dfrac{22}{7} \times \: r} \\ \\ \\ \\ \bf{\longmapsto \: 2 \times \: \dfrac{22}{7} \times \: 3.49} \\ \\ \\ \\ \bf{\longmapsto \: \dfrac{22 \times 2}{7} \times \: 3.49} \\ \\ \\ \\ \bf{\longmapsto \: \dfrac{44}{7} \times \: 3.49} \\ \\ \\ \\ \bf{\longmapsto \: \dfrac{44 \times 3.49}{7}} \\ \\ \\ \\ \bf{\longmapsto \: \dfrac{153.56}{7}} \\ \\ \\ \\ \bf{\longmapsto \: \cancel{\dfrac{153.56}{7}}} \\ \\ \\ \\ \bf{\longmapsto \: \red{21.93}}$

Hence, The perimeter is 21.93m.