The area of the bottom of a box of matches is 10 square cm. and its height is 1.5cm find the volume of a packet to hold two such boxes.
Answers
Answered by
0
Answer:
v=15 cm2
Step-by-step explanation:
area=10cm2 (l×b)
h=1.5cm
Now
volume= a×h
= 10 × 1.5
= 15 cm2
HOPE THIS IS USEFUL TO YOU!!!
Answered by
0
Answer:
The height of required packet is 3cm
area of base required is 10sqcm
so. volume=10*3=30CC
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