The area of the circle is 15 times the area of another circle. Find the ratio of their circumferences.
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Answers
Answer:
let the area of the smaller circle be x
according to question
area of bigger circle will be 15x
lets concentrate on smaller circle...
area of smaller circle is = πr^2
x = 22/7×r^2
x÷22/7=r^2
7x/22=r^2
therefore r = √7x/22
now we consider the bigger circle
area of bigger circle = πR^2
15x=22/7×R^2
15x÷22/7=R^2
105x/22=R^2
therefore R = √105x/22
now
circumference of smaller circle=2πr
=2×22/7×√7x/22
=44/7×√7x/22
now
circumference of bigger circle = 2πR
=2×22/7×√105x/22
=44/7×√105x/22
now the ratio of the smaller circle to the circumference of bigger circle
=44/7×√7x/22 : 44/7×√105x/22
now 44/7 and 22 and root and x get cancelled
therefore
7:105 .... remains ..
therefore the ratio of their circumference is 7:105
..
.
Step-by-step explanation:
Step-by-step explanation:
Answer:
Answer:
let the area of the smaller circle be x
according to question
area of bigger circle will be 15x
lets concentrate on smaller circle...
area of smaller circle is = πr^2
x = 22/7×r^2
x÷22/7=r^2
7x/22=r^2
therefore r = √7x/22
now we consider the bigger circle
area of bigger circle = πR^2
15x=22/7×R^2
15x÷22/7=R^2
105x/22=R^2
therefore R = √105x/22
now
circumference of smaller circle=2πr
=2×22/7×√7x/22
=44/7×√7x/22
now
circumference of bigger circle = 2πR
=2×22/7×√105x/22
=44/7×√105x/22
now the ratio of the smaller circle to the circumference of bigger circle
=44/7×√7x/22 : 44/7×√105x/22
now 44/7 and 22 and root and x get cancelled
therefore
7:105 .... remains ..
therefore the ratio of their circumference is 7:105