the area of the circle is trisected by two concentric circle.The radius of the smallest circle is
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Answer:
Let O be the center of a circle whose radius OA = 6 cm.
Its area = πr
2
=π(6)
2
=36πcm
2
Now, the area of this circle is trisected by two
concentric circles having radii OB and OC respectively.
∴ Area of the smallest circle ( with radius OC)
=
3
36π
cm
2
⇒π×OC
2
=12π⇒OC
2
=12
⇒OC=2
3
cm
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