The area of the circle that can be inscribed in a square of side 6cm is
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Answered by
8
--☺☺ HERE IS YOUR ANSWER ☺☺--
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circle(o,r) is inscribed in a square PQRS.
PS=PQ=SR=QR=6cm
AB=PS=6cm
AB = diameter = 6
AO = radius = 3cm
Area of circle = πr^2
=22/7×3×3
=28.28cm^2
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☺ HOPE IT HELPS YOU ☺..
THANKS....
_______________________________
circle(o,r) is inscribed in a square PQRS.
PS=PQ=SR=QR=6cm
AB=PS=6cm
AB = diameter = 6
AO = radius = 3cm
Area of circle = πr^2
=22/7×3×3
=28.28cm^2
_________________________________
☺ HOPE IT HELPS YOU ☺..
THANKS....
Answered by
3
Step-by-step explanation:
Hey dear here is your answer!!!!!
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The circle that can be inscribed inside the square would have it's center in exact center of the square and that point would be equidistant from all the sides of the square.
The distance between that point and side of square would be half of side of square:-
\frac{6}{2}
2
6
= r
r = 3cm
So, area of circle is:-
=πr²
=\frac{22}{7}
7
22
x 3 x 3
=\frac{198}{7}
7
198
=28.28 cm² (approx)
❣️⭐ Hope it helps you dear...⭐⭐❣️❣️
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