Question

The area of the circle whose centre is (0, – 4) and passes through the point (–1, 5), is

Answer 1

Answer:

r=

(−1−0)

2

+(5+4)

2

=

1+81

=

82

areaofcircle=πr

2

7

22

×82=

7

1804

=257.7sq.unit

Answer 2

Answer:

The Area of the circle is 257.71 sq.units

Step-by-step explanation:

Given that,

The centre of the circle is C(0,-4) Also given that the circle passes through the point A(-1,5)

The radius of the circle is distance between the centre of the circle and the point through which the circle passes.Hence,

$r=AC = \sqrt{(0 - ( - 1)) {}^{2} + ( - 4 - 5) {}^{2} } \\ = \sqrt{1 {}^{2} + 9 {}^{2} } = \sqrt{82} \: units$

Since,the radius is known,the Area of the circle is given by the relation

$A=πr^{2}$

Substituting the given radius we get

$A=π( \sqrt{82} )^{2} = 82 \times \frac{22}{7} \\ = 257.71 \: sq.units$

Therefore,the Area of the circle is 257.71 sq.units

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