Question

The area of the circumcircle of a right angle triangle whose sides are 6cm , 8cm and 10cm will be ? ​

Answer 1

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$\star\small\sf\underline\pink{Given:-}$

Three sides of triangle

• a = 6 cm

• b = 8 cm

• c = 10 cm

$\star\small\sf\underline\green{Solution:-}$

Circumradius of triangle is calculated by formula -

$:\implies\sf{R =\dfrac{ abc }{ \sqrt{[(a+b+c)(a+b-c)(a-b+c)(-a+b+c)] }} }$

$:\implies\sf{R =\dfrac{ 6\times 8\times 10 }{ \sqrt{[(6+8+10)(6+8-10)(6-8+10)(-6+8+10)]}} }$

$:\implies\sf{R =\dfrac{ 480 }{ \sqrt{24\times4\times8\times12} } }$

$:\implies\sf{R =\dfrac{ 480 }{ \sqrt{96\times 96}} }$

$:\implies\sf{R =\dfrac{ 480 }{ 96} }$

$:\implies\sf{R =5\:cm }$

Hence, circumradius is 5 cm.

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Answer 2

Here, as per the provided question we are asked to find the answer of the question –

GIVEN :

• 1st one = 6cm
• 2nd one = 8cm
• 3rd one = 10cm

Considering all of them as A, B and C....

TO FIND :

• The area of the the circum radius of a right angle triangle whereas, basic information is given = ____

STEP-BY-STEP INSTRUCTIONS :

Now, we will have to apply and specific formula which can be used to find the solution ·—

→ R = abc/√[(a+b+c) (a+b-c) (a-b+c) (-a+b+c)]

→ [ substituting the values ]

→ R = 6×8×10/√[(6+8+10) (6+8-10) (6-8+10) (-6+8+10)]

→ R = 480/√24×4×8×12

→R = 480/√96×96

→R= 480/96

→ R = 5cm

So, CircumRadius = 5cm when, sides are given as 6cm ,8cm and 10cm. ✔️