the area of the figure formed by|x|+|y|=2 is _(in sq.units)
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|x| + |y| = 2 ,
we know, there are four straight line in above equation .
e.g.,
x + y = 2 [ Line AB shows this equation ]
-x + y = 2 [ Line BC shows this equation ]
x - y = 2 [Line AD shows this equation ]
x + y = -2 [ Line BD shows this equation ]
we see that ,
the above equations form a rohmbus , whose side both diagonals are 4 unit
hence, area inclosed by{ |x| + |y| = 2} is area of rohmbus = 1/2 × product of diagonals
= 1/2 × 4 × 4 = 8 unit²
we know, there are four straight line in above equation .
e.g.,
x + y = 2 [ Line AB shows this equation ]
-x + y = 2 [ Line BC shows this equation ]
x - y = 2 [Line AD shows this equation ]
x + y = -2 [ Line BD shows this equation ]
we see that ,
the above equations form a rohmbus , whose side both diagonals are 4 unit
hence, area inclosed by{ |x| + |y| = 2} is area of rohmbus = 1/2 × product of diagonals
= 1/2 × 4 × 4 = 8 unit²
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Step-by-step explanation:
|x| + |y| = 2 ,
we know, there are four straight line in above equation .
e.g.,
x + y = 2 [ Line AB shows this equation ]
-x + y = 2 [ Line BC shows this equation ]
x - y = 2 [Line AD shows this equation ]
x + y = -2 [ Line BD shows this equation ]
we see that ,
the above equations form a rohmbus , whose side both diagonals are 4 unit
hence, area inclosed by{ |x| + |y| = 2} is area of rohmbus = 1/2 × product of diagonals
= 1/2 × 4 × 4 = 8 unit²
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