Question

the area of the floor of a conical 616 sq ft. the height is 2√15. find the slant height.

Answer 1

Area of floor of cone =$\pi r^{2}$ where r = radius of cone
 $\pi r^{2}$ = 616 sq ft 
 So, $r^{2}$ = 616 x 7/22 = 196 sq ft
  => $r^{2}$ = 196    => r = 14 ft
  We know that  l = $\sqrt{r ^{2}+ h ^{2} }$ where l = slant height ,   r   = radius of cone and h = height of cone.
  l =$\sqrt{14 ^{2} +( 2 \sqrt{5}) ^{2} }$
  l = 6$\sqrt{6}$ ft