The area of the given field is 3500 m² AL 25 m. AG 50 m AH 75 m. AB 100 m. DO 40 m, 1C 20 m, HE xm Find
the value of x
17m
20m
22m
25m
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Answer:
Total area = Area of ΔAFC+ Area of ΔAGD+ Area of trapezium FCEH+ Area of ΔBHE+ Area of ΔDGB
=21×AF×FC+21×AG×DG +21×BH×HE+21×BG×DG ⇒21×25×20+21×50×40+21×(20+x)×50 +21×25×20+21×50×40+21×(20+x)×50
⇒250+1000+(20+x)25+12.5x+1000−3500
⇒2250+500+25x+12.5x=3500
⇒
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