the area of the given figure is
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Area of the given figure = Area of two semi-circles + Area of two triangles + Area of a square
GC=GD+DC
GC=FE+12
GC=7+12
GC=19 m
And,
FA 22
22
GG
=FG+GA
=ED+GA
=12+GA
=10 m
So, total area is equal to sum of ar(ABCDG) and ar(FEDG),
Area=ar(ABCDG)+ar(FEDG)
=GC×GA+EF×ED
=19×10+7×12
=190+84=274 m
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