The area of the given rectangle is
(5x2 - 3x + 5) square units. A triangle inside the rectangle has an area of (-x2 + 5) square units. Find the area of the shaded portion lying outside the triangle.
A. 4x2- 3x square units
B. 6x2 - 3x + 10 square units
C. 4x2-3x add 10 sqaure unit.
D.6*3-3x sqaure unit
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Answer:
THE AREA OUTSIDE THE TRIANGLE IS (6x²+3x)
Step-by-step explanation:
TO FIND THE AREA OF PORTION LYING OUTSIDE THE TRIANGLE,
WE HAVE TO SUBTRACT THE AREA OF TRIANGLE FROM AREA OF SQUARE
SO,
AREA OF SQUARE-AREA OF TRIANGLE
(5x²-3x+5) - (-x²+5)
5x²+3x+5+x²-5
5x²+x²+5-5+3x
6x²+3x
SO,
AREA OF REGION OUTSIDE THE TRIANGLE IS (6x²+3x)
I HOPE YOU UNDERSTOOD THE QUESTION!!!
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