The area of the largest triangle that can be inscribed in a semi-circle of radius r is
(a)2r
(b)r ²
(c)r
(d)√r
Answers
Answered by
11
Answer:
The Area of ∆ is r² square units.
Among the given options option (b) r² square units is the correct answer.
Step-by-step explanation:
Given :
Let the Radius of the Semicircle be ‘r’ units.
Base of the largest triangle that can be inscribed in a semicircle is the diameter of a circle and and height of the ∆ is the radius of a circle.
Base of ∆ = diameter = 2r
Height of ∆ = r
Area of ∆ = ½ × base × height
Area of ∆ = ½ × 2r × r
Area of ∆ = r²
Hence, the Area of ∆ is r² square units.
HOPE THIS ANSWER WILL HELP YOU….
Answered by
1
The
answer will be r^2.
Here is how.
A semicircle has the largest triangle's base as its diameter, and its perpendicular or height as its radius
1/2 × base × height
= 1/2 × 2r ×
= r^2
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