Question

The area of the parallelogram ABCD is 90 cm2

. Find

(i) ar gm ABEF (|| )

(ii) ar ABD ( ) Δ

(iii) ar BEF ( ) ​

Answer 1

Answer:

1)90cm2,

Step-by-step explanation:

(i) area of rectangle ABEF = area of parallelogram ABCD

because , one common side is AB of parallelogram and rectangle and hight of both parallelogram is same as Breadth of rectangle .

hence, area of rectangle ABEF = 90 cm²

(ii) area of ABD = half of area of parallelogram { see attachment it is clear that , diagonal is divided by two equal of parallelogram, here BD is diagonal , that's why are(ABD) = ar(ABCD)/2 }

hence, ar(ABD) = 90cm²/2 = 45 cm²

(iii) ar(BEF) = half of ar(ABEF) = 45 cm² [ similarly diagonal of rectangle divide its two equal part ]

Answer 2

Answer:

ar gm ABEF (|| )= 90

ar ABD ( ) Δ=45

ar BEF ( ) =45

Step-by-step explanation:

here we can write area of prallelogram ABCD is equal to area of parallelogram  ABEF { ab is common side}

so,

ABCD=ABEF

,ABEF=90cm2

similarly

area of ABD [Draw a diagnoal BD]

Area of ABD=1/2[area of ABCD}

Area of ABD=1/2[90]

Area of ABD=45cm2

again

area of BEF [Draw a diagnoal BF]

Area of BEF=1/2[area of ABEF}

Area of BEF=1/2[90]

Area of BEF=45cm2

hope it was helpful.